Re: basic expression question

Oh, sure take the easy way out.

I was really hoping to use a 3rd order differential equation to
interchange 1 and 0.

On Aug 3, 10:04 pm, Jarrod Bell <jar...@guilink.com> wrote:
> The correct transform to use is:
> 1-value
>
> This way if the captured value is 1, the result is 0, and vice versa.
>
> Jarrod
>
> On Aug 4, 12:42 pm, Fiasco <dgvoll...@gmail.com> wrote:
>
>
>
> > Tried this as abs(value - 1) as well.
>
> > What I'm ending up with is:
>
> > When value = 1 I end up with 0
> > When value = 0 I end up with 65535
>
> > On Aug 3, 9:26 pm, Fiasco <dgvoll...@gmail.com> wrote:
>
> > > I have two possible regex values:
> > > 1 and 0
>
> > > These are assigned to a token [tokenvalue]
> > > data type analog
> > > target type digital
> > > token type token
> > > transform abs([tokenvalue]-1)
> > > Min value 0
> > > Max Value 0
>
> > > Will this correctly transform 1 into a 0 and 0 into a 1?
>
> > > 0-1 = -1
> > > abs(-1) = 1
>
> > > 1-1 = 0
> > > abs(0) = 0
>
> > > Yes?- Hide quoted text -
>
> - Show quoted text -

--
You received this message because you are subscribed to the Google Groups "CommandFusion" group.
To post to this group, send email to commandfusion@googlegroups.com.
To unsubscribe from this group, send email to commandfusion+unsubscribe@googlegroups.com.
For more options, visit this group at http://groups.google.com/group/commandfusion?hl=en.